The Discovery of Mesomatter
Just as the muons in atomic binding-energy fields emanate from muoprotonic ergomatter, even so the pions in nuclear strong force fields emanate from pioprotonic mesomatter (or mesonic substance).
The equation for the charged pion is very exact and very revealing! The electron base eb = 4pAP/c2 is 9.077,644,4 x 10-28 gm or 0.996,4.96,6 emu. Multiply this by 2 x 137.036,02, and we get 273.111.860 emu for the mass of the charged pion base. But its charge requires the addition of four more small particles:
1 photino (0.012,972 emu), 2 P-gyrinos (2 x 0.000,578,667), and 1 q-gyrino (0·000,586,673).
Charged Pion Base = 2Aeb = 273.111,860
+1 Photino = +0.012,972
+2 P-gyrinos = +0.001,157+1
q-gyrino = +0.000,587
If we compare this with the measured 139.5688 Mev = 273.126,576; find that our formula could not possibly be more exact!
Armed with such an exact formula, let us see what it reveals about the structure of the charged pion and the nuclear strong force which it obviously contains:
Aeb = 2A (4pAP )/c2 = 8pA2P/c2 but where P = hRu/2pc
So 8pA2hRu/2pc3 = 4A2hRu and where Ru = c2/G
Thus Aeb= 4A2(h/cG ) ...
Let's hold our horses right here! For we've just discovered (even if it is upside down) our nuclear refracted gravity or strong force constant S = cG/h ! We have called attention to c/h before as our macrocosmic converter. Physicists have claimed that gravity can have nothing to do with the nuclear strong force because it is too weak. You might just as well say that you can't set fire to a leaf with mere sunlight. Oh, yes, you can, if you have a strong enough lens. Gravity emanates, as we shall see, from the ontomatter at the heart of the cosmos. Metamatter and photomatter combine in a most ingenious way to form the lens. Every lens, of course, has an index of refraction c/v. Well, in this case c/h is our index of refraction! You will object "But h is an energy-time measured in erg-seconds. not a velocity." Well, the answer is as with G and so many of our other constants: if you move it into the right category, it becomes a velocity. And so c/h, our macrocosmic converter, becomes our index of refraction for refracting gravity with light.
But how do we know whether it really works?Very simply. We will try it out:
S = cG/h = 3.019,198 x 1029 cm3/gm-sec2 (with h as a velocity) .
Here's a tough problem. What is the binding energy of element #104 (Rutherfordium) if it has an atomic mass of 264?
The binding energy formula generally given in the physics books is
264BE104 = aA - bA 2/3 - cZ(Z-1)/A 1/3 - d(N-Z)2/A ± d/A 3/4 (Mev)
A = atomic mass = 264 a = 15.8 d = 23·7
Z = no. of protons = 104 b = 17·8 d = 34 if mass is even
N = no. of neutrons = 160 c = 0.71
This formula yields a binding energy 264BE104 = 1971.057,213 Mev.
Our equation is 264BE104 = Sm1m2/rw-binder (ergs).
(The binder is one pion± with a wave radius 1.413,847 x 10-13)
The first mass m1 here is the atomic mass matomic = 264.The second mass m2 here is the basic unit of the alpha particle as the product of two protons and neutrons, which are 2mpmn
264BE104 = (3.019,198 x 1029) x 264 x 2 x 1.672,614 x 1.674,920 x 10-48/1.413,847 x 10-13
264BE104 = 3.158,733 x 10-3 erg.
Divide this by 1.602,192 x 10-6 erg/Mev, and we get 1971.507 Mev
Close enough at our present stage of understanding!
Let us now return to our formula for the charged pion 4A2(h/cG). What is the purpose of the 4A2?
The binding pion± catches its proton muomagnetically with its interchange photino and the three charge gyrinos listed in Chapter II. It thus establishes with it an atomic binding-energy field rbe = K/mbec2 But when this is multiplied by the constant A = 137.036,02, it is transformed into a photomatter wave-radius equation:
rw = Arbe = AK/mbec2 = U/mbec2 = hc/2p(mbec2) = h/2pcmbe , where U = hc/2p = AK
Then our pion± captures another proton and transforms its field also into a photomatter wave-radius field
rw = Arbe This removes the A2. As the pion now draws the two protons and binds them together, they become like a double mass with half the wave-radius, a relationship of 2 to 1/2, or 4 to 1. Hence the presence of the 4 in the equation. So we now see that the equation makes perfect sense!
What about the neutral pion? Its equation is mec3/4pe2. This works out to 264.338,730 emu, just one virtuon (e/Ru = 0.221,560 emu) and one R-gyrino (R/c2 = 0.000,594,787) above its measured mass of 264.116,276 emu. This equation can also be written in the form:
melectron(cG)/mergoelectron(e2) where mergoelectron =4p/Ru
When an electron and proton are converted into a neutron, the electron becomes an ergoelectron and the proton retains its virtuon but with its charge neutralized. So the field between the neutral pion and the neutron is the neutromagnetic field between the virtuon± in the piono and the virtuon-/+ inside the neutron. As the field then shifts to include the virtuon inside the second neutron, the dynamic product of these two virtuons becomes e2/Ru2. The e2 in the numerator then cancels with the e2 in the denominator of the pion° to produce 1/Ru2, the equation of the binding graviton. So once more we see the working of gravity in different ways inside the pions of mesomatter.
When we discovered the photoproton by moving the photon through the categories of time, energy, and mass into the category of light, we discovered at the same time three other particles which are shown in Chapter IV, the macrowave kineton (elementary particle of antimatter active in our brain waves), the radio-wave energion (elementary particle of ergomatter) and the infrared thermeton (elementary particle of mesomatter). This teaches us that mesonic pioprotonic mesomatter in the category of mass is also our thermodynamic heart substance. For the thermeton Gh/2p in Intercategorical Physics can be transformed into the mesoelectron simply by dividing out the constant of gravity G!
Go to Chapter VII
(The Chapter on Metamatter)
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