**The Intercategorical Physics**

**Chapter III**

**The Three Neutral Currents**

**(Could these be the Leptons we're looking for?)**

Now, if you think after all this that we just concocted this all as a mere fantasy in our head, we suggest that you try it yourself some time. You will soon find out that we human beings just aren't clever enough to invent whole systems of reality that actually work out in all their details. Of course, we would be the first to admit that this Intercategorical Physics still has a lot of wrinkles to iron out, but basically it is just as true as G_d's Word itself for it is the insight from G_d's Word about the creation of the universe as a rational system through his Logos (the ta)as it works out in terms of simple mathematical logic.

For the basic rip in the fabric of reality was the
discovery of the radius of the universe R = c^{2}/G. Ever since then, the fabric
of the universe keeps unraveling and unraveling and unraveling revealing discovery after
discovery after discovery every day in the year that we work on it. And why should it not
be so? If G_d really created the universe, and we know he did, it is logical to assume
that the ultimate physics of the millennium will be the one that ties everything together
through the radius of the universe R_{u} = cT_{u} to the time of the
universe T_{u} that goes back to his original act of creation in the fireball of
Genesis 1:1: "In the beginning G_d created the heavens and the earth."

Our next step now must be to derive the equations for the three neutrinos that function in the different electric and neutral currents. The photon we have discovered may be the ultimate vehicle for light in the universe, but it is manifestly too infinitesimal to function as the interchange particle in electromagnetic fields. What particle could this be?

**The Photon Neutrino (Photino)**

Well, in our Intercategorical Physics we have two
converters, the microcosmic converter h/c = 2.210,261 x 10^{-37} gm-cm, and the
macrocosmic converter c/h = 4.524,353 x 10^{36} gm^{-l} cm^{-1}.
By simply applying our macrocosmic converter c/h to our microcosmic photon, we discover
its macrocosmic counterpart the photon neutrino or photino, for short

c/h (m_{photon}) = c/h (h/2pcR_{u}) = m_{photino }= 1/2pR_{u = }1.181,718 x 10^{-29} gm = 0.012,972 emu

Now, you will say, how can the mass of a neutrino equal the inverse of the circumference of the universe? Well, all this equation says in Intercategorical Physics is that the mass of the photino varies inversely as the circumference of the universe and that this variation may be converted into an equality in any calculation involving a measuring system that guarantees the mass of particles in relation to their volume by means of the density of water.

The Electron Neutrino (Electrino)

The mass of the electron neutrino, or electrino
for short, can also be determined approximately from its role as the binder of the
electron and proton inside the neutron: m_{electrino} = n - p - BE/c^{2 }The
total electromagnetic energy BE binding the electron at the surface of the proton of
optical radius^{}

1.1 x 10^{-13} )cm is given by:

BE = q^{2}/r_{p} = K/r_{p} =
2.307.121 x 10^{-19} erg-cm/1.1 x 10^{-13} cm = 2.0974 x 10-6 erg

The mass of this binding energy may be found now by
dividing the BE by c^{2} (= 2.997,925 x 10^{10})^{2} which is
equal to 8.987,554 x 10^{20} = 2.3337 x l0^{-27} gm. If we divide this in
turn by the mass of the electron 9.109,558,6 x 10^{-28} gm, we get the mass of the
BE in electron mass units = 2.5618 emu. But the difference in mass between the neutron
1838.6402 and the proton 1836·1089 emu is only 2.5313 emu. Hence, when we subtract 2.5618
from 2·5313, we get the negative difference of -0.0306 emu for our electrino. But the
difference comes out negative because the binder of the proton and electron inside the
neutron is an antielectrino. Therefore, the mass of the antielectrino should be
approximately 0.0306 emu. Later we found the actual formula for the electrino to be 1/eR_{u}
where e is the exponential constant 2.718,281,8. This gives us the exact value for the
electrino as 2.731·487 x 10^{-29} gm = 0.029,985 emu, which is very close to the
other.

The Muon Neutrino (Muino)

Similarly we found the actual formula for the
muon neutrino or muino, for short, to be 1/R_{u}. This gives us the exact value
for the muino as 7.424,951 x 10^{-29} gm = 0.081,507 emu. Notice also that the
mass of the muino is the square root of the graviton. This means that whenever two muinos
come together in a dynamic relation such as F = Xmm/r^{2}, the product of their
masses must produce the graviton!

One of the unsolved problems in modern physics is the
question, "What is the electric particle that travels down a wire at the velocity of
light c? It is certainly not the electron, for electrons have been found to interchange
from atom to atom down a wire at the speed a caterpillar can crawl, about 1
centimeter/second. At that rate it would take 11 and a half days to telephone someone in a
town only 10 kilometers away. No, just as the sun is orbited by the planets and the
planets in turn by their moons, even so the electrons revolving around the nucleus of the
atom are themselves orbited by a host of tiny neutrinos, and the neutrinos in turn by
their charge gyrinos. The only difference is that the electrons orbit around the atomic
nucleus in an electromagnetic field determined by the electromagnetic constant K =
2.307,121 x 10^{-19}

whereas the neutrinos orbit around the electron in a photomagnetic field determined by the weak force constants W = hP/c or hq/c or hR/c. Such is the complex picture of the subatomic and subelectronic world

that is now emerging from our Intercategorical Physics. It is by adding these neutrinos as satellites that the material electron can be transformed into an ergoelectron or mesoelectron or photoelectron or metaelectron or ontoelectron. In short, the neutrinos are added to the electron like the mesons to the protons and neutrons to form the different kinds of matter. Apparently, the photinos orbit the electron on a hP/c plane parallel to the radiation of the photons along the circumferential surface of the universe, the electrinos orient themselves on a hq/c plane parallel to that of the electromagnetic field that unites the circumference with the axis, and the muinos flow along a hR/c plane parallel to the gravity field along the radius of the universe.

From this we can infer:

(1) That the photinos (1/2pR_{u}) are the circumferential particles that
interchange in electric fields along wires and therefore flow along the electrons to
produce electric currents;

(2) That the electrinos (1/eR_{u}) are the
exponential-curving, logarithmic-spiraling particles operating in the magnetic flux of
magnetic fields like the binding field between the electron and proton inside the neutron
and the magnetic field surrounding the earth, for the magnetic flux loops along the
circumference across the equator to enter and exit the radii at the poles; and

(3) That the muinos (1/R_{u}) are the radial
particles involved in the gravity flux of gravity fields like that of the earth and
also in the nuclear flux of strong force fields within the atomic nucleus, for they can
unite as gravitons (1/R_{u}) in gravity fields F_{g} = GmM/r^{2}
or separate as muinos (1/R_{u}) in nuclear fields F_{s} = (cG/h)n_{l}n_{2}/r^{2}.
Therefore, we may conclude that when an electric current flows down a wire, it is because
photinos are from one electron to the next at the velocity of light.

Now the electron base minus all charges is given by the
formula 4pAP/c^{2} (which is exactly 4pA [ = 4p x 187. 036, 02] x mass of
P-gyrino ) = 9.077,644,4 x 10^{-28} gram = 0.996,496,6 electron mass units. To
this we must add the following charges:

Electron base
= 0.996,496,6

3 P-gyrinos in hP/c plane = 0.001,736,0 = 3 x 0.000,578,667 emu

2 q-gyrinos in hq/c plane = 0.001,173,3 = 2 x 0.000,586,673

1 R-gyrino in hR/c plane = __0.000.594.8__ = 1 x 0.000,594,787

Thus the charged electron is 1.000,000,7 emu (the remainder of 0.000,000,7 is due to the
inaccuracy of the calculation).

Now the two q-gyrinos revolve opposite each other in the electromagnetic plane, so that only one q-charge of 4.803,250,4 c.g.s. is in electric space while only one q-charge is in magnetic time at any given moment. Also the preponderence of P-charges orients the charge negatively towards the spatial circumference of the universe rather than positively towards its nuclear gravity radius. Therefore, we can say that this electron is circumferentially extroverted as a negatron. If it had one P-charge and 3 R-charges, it would radially introverted as a positron.

Now if we take a very small spherical energy field of 4p steradians at the tip of an expanding radius of the universe R_{u},
we get the intercategorical formula 4p/R_{u} = 4pG/c^{2} for the mass of the ergoelectron base. Then, if we
take this ergoelectron base 4p/R
= 9.330,468,1 x 10^{-28} gram = 1·024,250,4 emu and place it on the hypotenuse of
an electron triangle and place the virtuon (the positron inside the proton as its positive
charge e/R_{u} = 2.018,310,9 x 10^{-28} gm = 0.221,559,7 emu) on one of
its legs, then the Pythagorean difference of the squares gives us the exact formula for
the electron (16p^{2} -
e^{2})^{1/2}/R_{u}, which gives us

where in SPACE we have an electron = (16p^{2}-e^{2})/R_{u}
and

where in TIME we have a virtuon = e/R_{u}
(inside the proton) and

where in MASS we have 2 mesoelectrons = 2(h/2p) and

where in ENERGY we have an ergoelectron = 4p/R_{u} and

where in LIGHT (Manifestation) we have 2 photoelectrons
= (4p/R_{u})(1+(Pc/2p)^{2})^{1/2}

**FIGURE 1**

(9.330,468,1 x l0^{-28})^{2} =
8.705,763,5 x 10^{-55}

-(2.018,3l0,9 x 10^{-28})^{2} = __-0.407,357,9 x 10 ^{-55}__

8.298.405,6 x l0

We are now in a position to calculate the other kinds of electrons:

Electron Base, e_{b }
0.996,496,6 emu

+ 2 photinos
+0.025,944,6
= 2 x 0.012,972,3

+ 3 gyrinos
+0.001,784,4
= 3 x 0.000,594,787

+ remainder __
+0.000,024,8__

Ergoelectron Base
=1.024,250,4 emu
= 4p/R_{u }= 9.330,468,1
x 10^{-28} gram

+ 6 gyrinos __
+0.003,568,7__
= 6 x 0.000,594,787

Ergoelectron, e_{e }
=1.027,819,1

+ 1 photino
+0.012,972,3

+ 1 electrino
+0.029,984,8

+ 1 muino
+0.081,507,2

+ 3 gyrinos
+0.001,784,4
= 3 x 0.000,594,787

+ remainder __
+0.000,039,7__

Mesoelectron Base
=1.154,107,5

+ 6 gyrinos __
+0.003,568,7__

Mesoelectron, e_{m}
=1.157,676,2 emu
= h/2p = thermeton (Gh/2p)/G

+ 2 photinos
+0.025,944,6

+ 1 muino
+0.081,507,2
{neutron-proton =
1838.640,238-1836.108,947}

+ 1 gyrino
+0.000,594,8
{ =2.531,291 and 1/2 is =
1.265,645,5 }

-remainder __
-0.000,077,3__

Photoelectron, e_{f}
=1.265,645,5 emu
= 2p/R_{u} (1 + (Pc/2p)^{2})^{1/2}

+ 3 photinos
+0.038,916,9

+ 2 electrinos
+0.059,969,6
= 2 x 0.029,984,8

+ 2 muino
+0.163,014,4
= 2 x 0.081,507,2

+ 2 gyrinos
+0.001,189,6
= 2 x 0.000,594,787

- remainder __
-0.000,050,3__

Metaelectron, e_{m}
=1.528,685,7 emu
= 4pq^{3 }= 1.392,565,2
x 10^{-27} gram

+ 2 photinos
+0.025,944,6

+ 1 electrino
+0.029,984,8

+ 2 gyrinos
+0.001,189,4

remainder __
-0.000,134,5__

Ontoelectron Base
=1.585,670,0

+12 gyrinos
+0.007,137,4
= 12 x 0.000,594,787

+ remainder __
+0.000,184,7__

Ontoelectron, e_{o}
=1.592,992,1
= 4pR^{3} = 1.451,145,5
x 10^{-27} gram

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